{"id":2955,"date":"2022-10-23T14:50:03","date_gmt":"2022-10-23T14:50:03","guid":{"rendered":"https:\/\/careerssutra.com\/?p=2955"},"modified":"2022-10-24T09:32:11","modified_gmt":"2022-10-24T09:32:11","slug":"ncert-solutions-for-class-10-maths-chapter-11-constructions","status":"publish","type":"post","link":"https:\/\/careerssutra.com\/ncert-solutions-for-class-10-maths-chapter-11-constructions\/","title":{"rendered":"NCERT Solutions for Class 10 Maths Chapter 11 Constructions"},"content":{"rendered":"\n
NCERT Solutions for Class 10 Maths Chapter 11 Constructions<\/h5>\n\n\n\n
In this chapter, you will be dealing with geometric construction problems. NCERT solutions for Class 10 Maths chapter 11 Constructions provide a step-by-step explanation for each problem in the practise exercises. Construction Class 10 Maths chapter 11 NCERT solutions will be useful for homework and board exam preparation. NCERT solutions for Class 10 Maths Chapter 11 are intended to reduce time spent searching for solutions. NCERT solutions for Construction class 10 maths chapter are a valuable resource for enhancing your preparation. NCERT solutions for science and math from classes 6 to 12 are available here. NCERT solutions for class 10 are also available here. Read on to learn more about NCERT solutions Class 10 maths chapter 11 pdf download and other details.<\/p>\n\n\n\n
NCERT Solutions for Class 10 Maths Chapter 11 <\/strong>Constructions Excercise: 11.1<\/strong><\/h2>\n\n\n\n
In each of the following, give the justification of the construction also: Q1 <\/strong>Draw a line segment of length 7.6 cm and divide it in the ratio 5 : 8. Measure the two parts.<\/p>\n\n\n\n
Answer:<\/strong><\/h3>\n\n\n\n
Steps of construction:-<\/strong><\/p>\n\n\n\n
(i) Draw a line segment AB of measurement 7.6 cm (length).<\/p>\n\n\n\n
(ii) Now draw an acute angle AC with line segment AB.<\/p>\n\n\n\n
(iii) Now cut 13 equal points on the line AC where the zeroth point is A.<\/p>\n\n\n\n
(iv) Join the 13th point with point B. So the new line is BA 13 <\/sub>.<\/p>\n\n\n\n
(v) Now, from point A 5 <\/sub>draw a line parallel to BA 13 <\/sub>on line AB. Name the point as D.<\/p>\n\n\n\n
The point D is the required point which divides the line segment in the ratio of 5: 8.<\/p>\n\n\n\n
The length of the two parts obtained is 2.9 cm and 4.7 cm for AD and DB respectively.<\/p>\n\n\n\n